KCET2016ChemistryStructure of Atom
The energy of electron in the ( n^ th ) Bohr orbit of H-atom is
Options
- A( -13.6 n² eV )
- B( -13.6 n eV )
- C( -13.6 n⁴ eV )
- D( -13.6 n³ eV )
Correct answer
A. ( -13.6 n² eV )
Step-by-step solution
The energy of ( e⁻ )in the nth Bohr orbit of H-atom is given by expression [ array l E_ n = -2 ² m e⁴ Z² n² h² (4 ₀ )² =-13.6 Z² n² e V array ] Since ( Z=1 ) for hydrogen above equation can be further simplified to [ E_ n = -13.6 n² eV ]