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KCET2015ChemistryStructure of Atom

The two electrons have the following set of quantum numbers : [ array l P=3,2,-2,+ 1 2 Q=3,0,0,+ 1 2 array ] Which of the following statement is true?

Options

  1. A( P ) and ( Q ) have same energy
  2. B( P ) has greater energy than ( Q )
  3. C( P ) has lesser energy than ( Q )
  4. D( P ) and ( Q ) represent same electron

Correct answer

B. ( P ) has greater energy than ( Q )

Step-by-step solution

For electron P , the values of quantum numbers are n=3, I=2, m l=-2 and s=+1 / 2 . For electron Q quantum numbers are n=3, I=0, m l=0 and s=+1 / 2 . Therefore, from the quantum number values, electron P belongs to 3 d- orbital and electron Q to 3 s - orbital. Energy of the orbital is s < p < d < f . Hence, energy of electron P is higher than electron Q .

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