Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
KCET2010ChemistryStructure of Atom

The wave number of the spectral line in the emission spectrum of hydrogen will be equal to 8 9 times the Rydberg's constant if the electron jumps from

Options

  1. An =3 to n =1
  2. Bn =10 to n =1
  3. Cn =9 to n =1
  4. Dn =2 to n =1

Correct answer

A. n =3 to n =1

Step-by-step solution

Wave number of spectral line in emission spectrum of hydrogen, v =R_ H ( 1 n₁² - 1 n₂² ) ...(i) Given, v = 8 9 R_ H On putting the value of v in Eq. (i), we get aligned 8 9 R _ H &= R _ H ( 1 n ₁² - 1 n ₂² ) 8 9 &= 1 (1)² - 1 n ₂² 8 9 -1 &=- 1 n ₂² 1 3 &= 1 n ₂ n ₂ &=3 aligned Hence, electron jumps from n ₂=3 to n ₁=1

Practice Structure of Atom on Quantrex Academy →

More from Structure of Atom

The frequency of photon which is emitted during a transition of electron of He ^+ ion from fifth energy level to third energy level will be: 2026Which of the following statement is correct ? 2026The wavelength of a particular electron transition for He ⁺ is 100 nm. The wavelength (in Å ) of H atom for the same transition is 2025The energy of second Bohr orbit of hydrogen atom is -3.4 eV. The energy of the fourth Bohr orbit of the He ⁺ ion will be 2025The work function of Cu is 7.68 10⁻¹⁹ ~J . If photons of wavelength 221 nm are made to strike the surface of the metal, the kinetic energy (in J) of the ejected electrons will be ( 2025In an element with atomic number (Z) 25 , the number of electrons with ( n+l ) value equal to 3 and 4 are x and y respectively. The value of (x+y) is 2025a , b , c , d are electromagnetic radiations. Frequencies of a , b are 3 10¹⁵ ~Hz , 2 10¹⁴ ~Hz , respectively, whereas wavelength of c, d are 400 ~nm , 750 ~nm , respectively. The 2025The number of electrons with magnetic quantum number, m _l=0 in the elements with atomic numbers Z=24 and Z=29 are respectively 2025 Full Structure of Atom list All KCET PYQs