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KCET2018MathematicsApplication of Derivatives

The maximum area of a rectangle inscribed in the circle ( (x+1)²+(y-3)²=64 ) is

Options

  1. A( 64 sq . ) units
  2. B( 72 sq . ) units
  3. C( 128 ) sq. units
  4. D( 8 ) sq. units

Correct answer

C. ( 128 ) sq. units

Step-by-step solution

(x+1)²+(y-3)²=64x²+x²=(16)²2 x²=16.16x²=8.16x=8 2 Given rectangle is a square Area of square is =8 2 8 2 =128 s q . units

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