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KCET2008MathematicsCircle

The equation of the smallest circle passing through the points (2,2) and (3,3) is

Options

  1. Ax²+y²+5 x+5 y+12=0
  2. Bx²+y²-5 x-5 y+12=0
  3. Cx²+y²+5 x-5 y+12=0
  4. Dx²+y²-5 x+5 y-12=0

Correct answer

B. x²+y²-5 x-5 y+12=0

Step-by-step solution

Let the points be A=(2,2) and B=(3,3) . Since, the circle passing through these points, so they satisfie the equation of the circle. Now, taking option (b), Let S x ²+ y ²-5 x -5 y +12=0 At A =(2,2)2²+2²-5(2)-5(2)+12=0 0=0 At B =(3,3)3²+3²-5(3)-5(3)+12=0 0=0 Hence, option (b) is correct.

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