x²+y²-6 x-6 y+4=0, x²+y²-2 x-4 y+3=0, x²+y²+2 k x+2 y+1=0 . If the radical centre of the above three circles exists, then which of the following cannot be the value of k ?

Step-by-step solution

Given equation of circles are S₁ x²+y²-6 x-6 y+4=0 S₂ x²+y²-2 x-4 y+3=0 and S₃ x²+y²+2 k x+2 y+1=0 Now, radical axis of circle S₁ and S₂ is S₁-S₂=0 x²+y²-6 x-6 y+4-x²-y²+2 x -4 x-2 y+1=0 4 x+2 y-1=0 Radical axis of circle S₂ and S₃ is -3=0 S₂-S₃=0 x²+y²-2 x-4 y+3-x²-y²-2 k x -(2+2 k) x-6 y+2=0 (2+2 k) x+6 y-2=0 array lr & 24-4-4 k 0 & 20-4 k 0 & k 5 array