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KCET2013MathematicsDefinite Integration

The value of _ -1 ² |x| x d x , is

Options

  1. A0
  2. B1
  3. C2
  4. D3

Correct answer

B. 1

Step-by-step solution

Let I= _ -1 ² |x| x d x= _ -1 ⁰ (- x x ) d x+ ₀² ( x x ) d x ( |x|= array rll x, & if & x 0 -x, & if & x < 0 array ) .=- _ -1 ⁰ d x+ ₀² d x=-[x]_ -1 ⁰+[x]₀²=-[0+1]+[2-0]=-1+2=1

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