KCET2011MathematicsDefinite Integration
The value of ₀⁴|x-1| d x is
Options
- A5 2
- B5
- C4
- D1
Correct answer
B. 5
Step-by-step solution
aligned ₀⁴|x-1| d x &= ₀¹-(x-1) d x+ ₁⁴(x-1) d x &=- [ x² 2 -x ]₀¹+ [ x² 2 -x ]₁⁴ &=-[1 / 2-1]+[8-4-1 / 2+1] &=-(-1 / 2)+(4+1 / 2) &=1 / 2+9 / 2 &=5 aligned