Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
KCET2010MathematicsDefinite Integration

₀^ / 4 x+ x 3+ 2 x d x is

Options

  1. A1 4 3
  2. B3
  3. C1 2 3
  4. D2 3

Correct answer

A. 1 4 3

Step-by-step solution

₀^ / 4 x+ x 3+ 2 x d x= ₀^ / 4 ( x+ x) 4-(1- 2 x) d x= ₀^ / 4 ( x+ x) 4-( x- x)² d x Put t=( x- x)d t=( x+ x) d x= _ -1 ⁰ d t (4-t² ) = _ -1 ⁰ dt (2+ t )(2- t ) = 1 4 _ -1 ⁰ [ 1 2+t + 1 2-t ] d t= 1 4 [ (2+t)- (2-t)]_ -1 ⁰ aligned &= 1 4 [ ( 2+ t 2- t ) ]_ -1 ⁰ &= 1 4 [ (1)- ( 1 3 ) ] &= 1 4 3 aligned

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

₀^1 2 x+5 x^2+3 x+2 ~d x= 2025₀^1 x^ 5 / 2 (1-x)^ 3 / 2 ~d x= 2025_ n [ 1 n^2 ^2 1 n^2 + 2 n^2 ^2 4 n^2 + 3 n^2 ^2 9 n^2 + + 1 n^2 ^2 1 ]= 2025₀^1 x Sin ⁻¹ x d x= 2025_ - 2 ^ 2 (x-[x]) d x= 2025₀^2 x^2(2-x)^5 d x= 2025If f(x)= Max x^3-4, x^4-4 , and g(x)= Min x^2, x^3 , then _ -1 ^1(f(x)-g(x)) d x= 2025_ n 2 n [ 2 n + 2 2 n + 3 2 n + + 2 ]= 2025 Full Definite Integration list All KCET PYQs