The degree of the differential equation 1+ ( d y d x )^2+ ( d^2 y d x^2 )^2= [3] d^2 y d x^2 +1 is

Step-by-step solution

Given, 1+ ( d y d x )^2+ ( d^2 y d x^2 )^2= [3] d^2 y d x^2 +1 On cubic both sides, we get aligned & [1+ ( d y d x )^2+ ( d^2 y d x^2 )^2 ]^3= ( d^2 y d x^2 +1 ) & [1+ ( d y d x )^2 ]^3+ ( d^2 y d x^2 )^6+3 [1+ ( d y d x )^2 ] d^2 y d x^2 & [1+ ( d y d x )^2+ ( d^2 y d x^2 )^2 ]= d^2 y d x^2 +1 aligned So, degree of the differential equation is 6 .