If ( A= 1 [ array ll ⁻¹( x) & ⁻¹ ( x I I ) ⁻¹ ( x I I ) & ⁻¹( x) array ] ) then ( A-B ) is

Step-by-step solution

Given that, ( A= 1 [ array ll ⁻¹(I X) & ⁻¹ ( x ) ⁻¹ ( x ) & ⁻¹( X) array ] ) and ( B= [ array ll - ⁻¹( x) & ⁻¹ ( x ) ⁻¹ ( x ) & - ⁻¹( x) array ] ) So, ( A-B= 1 [ array ll ⁻¹( x)+ ⁻¹( x) & ⁻¹ ( x )- ⁻¹ ( x ) ⁻¹ ( x I I )- ⁻¹ ( x I I ) & ⁻¹( x)+ ⁻¹( x) array ] ) Since, ( ⁻¹ x+ ⁻¹ x= 2 ) and ( ⁻¹ x+ ⁻¹ x= I 2 . ) So, ( A-B= 1 [ array ccc I I 2 & 0 0 & 2 array ]= 1 2 [ array ll 1 & 0 0 & 1 array ] ) ( = 2 I 1 = 1 2 I )