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KCET2014MathematicsDifferential Equations

The value of ( [ a - b b - c c - a ] ) is equal to

Options

  1. A( 11 )
  2. B( 12 )
  3. C( 00 )
  4. D( 2[ a b c ] )

Correct answer

C. ( 00 )

Step-by-step solution

Given that, [ a - b , b - c , c - a ]=[ a - b ][( b - c ) ( c - a )]=[ a - b ][ b c - b a - c c + c a ]=[ a - b ][ b c - b a + c a ] Since c c =0 a ( b c )- a ( b a )+ a ( c a )- b ( b c )+ b ( b a )- b ( c a )=[ a b c ]-0+0-0+0-[ a b ]=0

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