Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
KCET2011MathematicsDifferential Equations

The general solution of ( d y d x )²=1-x²-y²+x² y² is

Options

  1. A2 ⁻¹ y=x 1-x² + ⁻¹ x+C
  2. B⁻¹ y=x ⁻¹ x+C
  3. C⁻¹ y= 1 2 ⁻¹ x+C
  4. D2 ⁻¹ y=x 1-y² +C

Correct answer

A. 2 ⁻¹ y=x 1-x² + ⁻¹ x+C

Step-by-step solution

Given, ( d y d x )²=1-x²-y²+x² y² ( d y d x )²= (1-x² )-y² (1-x² ) d y d x = (1-x² ) (1-y² ) d y (1-y² ) = (1-x² ) d x (on integrating) ⁻¹ y= x 2 1-x² + 1 2 ⁻¹ x+ C 2 2 ⁻¹ y=x 1-x² + ⁻¹ x+C

Practice Differential Equations on Quantrex Academy →

More from Differential Equations

The general solution of the differential equation (x y x ) d y= (y y x -x ) d x is 2025The general solution of the differential equation (x+y) d y=d x is 2025If Ax ^3+ Bxy =4 (A and B are arbitrary constants) is the general solution of the differential equation F(x) d^2 y d x^2 +G(x) d y d x -2 y=0 , then F(1)+G(1)= 2025If y=A t^2+ B t (A,B are parameters) is general solution of the differential equation f(t) y^ (t)+g(t) y^ (t)+h(t) y=0 then 2 f(t)+t^2 h(t)= 2025The general solution of the differential equation (2 x-y)^2 d y-2(2 x-y)^2 d x-2 d x=0 is 2025The general solution of the differential equation x x d y=(x x-y) d x is 2025If a and b are arbitrary constants, then the differential equation corresponding to the family of curves y= (a x+b) is 2025The general solution of the differential equation x y(y+2) d y+ (y^3-1 ) d x=0 is 2025 Full Differential Equations list All KCET PYQs