KCET2010MathematicsDifferential Equations
The order and degree of the differential equation y= d p d x x= a² p²+b² , where p = dy dx (here a and b are arbitrary constants) respectively are
Options
- A2,2
- B1,1
- C1,2
- D2,1
Correct answer
A. 2,2
Step-by-step solution
Given differential equation is y = ( dp dx ) x + a ² p ²+ b ² , ( p = dy dx ) y = [ d dx ( dy dx ) ] x + a ² ( dy dx )²+ b ² ( y - x d ² y dx ² )= a ² ( dy dx )²+ b ² ( y - x d ² y dx )²= a ² ( dy dx )²+ b ² Hence, order =2 and degree =2