KCET2026MathematicsDifferentiation
If y = [3] x + y , then dy dx =
Options
- Ax 3y^2 - 1
- B^2 x 3y - 1
- Cx 3y - 1
- D^2 x 3y^2 - 1
Correct answer
D. ^2 x 3y^2 - 1
Step-by-step solution
Given y = [3] x + y Cubing both sides, we get: y^3 = x + y Differentiating both sides with respect to x : 3y^2 dy dx = ^2 x + dy dx Rearranging the terms to solve for dy dx : (3y^2 - 1) dy dx = ^2 x dy dx = ^2 x 3y^2 - 1 Answer: ^2 x 3y^2 - 1