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KCET2023MathematicsDifferentiation

If u= ⁻¹ ( 2 x 1+x^2 ) and v= ⁻¹ ( 2 x 1-x^2 ) then d u d v is

Options

  1. A2
  2. B1-x^2 1+x^2
  3. C1
  4. D1 2

Correct answer

C. 1

Step-by-step solution

Here, u= ⁻¹ ( 2 x 1+x^2 ) .u=2 ⁻¹ x 2 ⁻¹ x= ⁻¹ ( 2 x 1+x^2 ) ] aligned & d u d x =2 1 1+x^2 & and v= ⁻¹ ( 2 x 1-x^2 ) aligned aligned y & =2 ⁻¹ x [ 2 ⁻¹ x= ⁻¹ ( 2 x 1-x^2 ) ] & d v d x = 2 1+x^2 aligned From Eqs. (i) and (ii), we get d v d x =1

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