KCET2023MathematicsDifferentiation
If u= ⁻¹ ( 2 x 1+x^2 ) and v= ⁻¹ ( 2 x 1-x^2 ) then d u d v is
Options
- A2
- B1-x^2 1+x^2
- C1
- D1 2
Correct answer
C. 1
Step-by-step solution
Here, u= ⁻¹ ( 2 x 1+x^2 ) .u=2 ⁻¹ x 2 ⁻¹ x= ⁻¹ ( 2 x 1+x^2 ) ] aligned & d u d x =2 1 1+x^2 & and v= ⁻¹ ( 2 x 1-x^2 ) aligned aligned y & =2 ⁻¹ x [ 2 ⁻¹ x= ⁻¹ ( 2 x 1-x^2 ) ] & d v d x = 2 1+x^2 aligned From Eqs. (i) and (ii), we get d v d x =1