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KCET2017MathematicsDifferentiation

General solution of differential equation ( d y d x +y=1(y 1) ) is

Options

  1. A( | 1 1-y |=x+C )
  2. B( |1-y|=x+C )
  3. C( |1+y|=x+C )
  4. D( | 1 1-y |=-x+C )

Correct answer

A. ( | 1 1-y |=x+C )

Step-by-step solution

Given differential equation, [ array l d y d x +y=1(y 1) d y d x =(1-y) d y (1-y) =d x array ] Integrating both the sides, we get [ array l d y (1-y) = d x - |1-y|=x+C | 1 1-y |=x+C array ]

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