KCET2024MathematicsFunctions
Let f: R R be defined by f(x)=x^2+1 . Then, the pre images of 17 and -3 . respectively are
Options
- A, 4,-4
- B3,-3 ,
- C4,-4 ,
- D4,-4 , 2,-2
Correct answer
C. 4,-4 ,
Step-by-step solution
For pre image of 17 , we have f(x)=x^2+1=17 x^2=16 x= 4 So, x -4,4 For pre image of -3 , we have f(x)=x^2+1=-3 x^2=-4( not possible ) Hence, no possible pre image.