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KCET2015MathematicsFunctions

If the function ( g(x) ) is defined by [ g(x)= ²⁰⁰ 200 + ¹⁹⁹ 199 + ¹⁹⁸ 198 + + ² 2 + +5, then g^ (0)= ]

Options

  1. A( 11 )
  2. B( 200 )
  3. C( 100 )
  4. D( 55 )

Correct answer

A. ( 11 )

Step-by-step solution

Given that, [ array l g(x)= ²⁰⁰ 200 + ¹⁹⁹ 199 + ¹⁹⁸ 198 + s+ ² 2 + +5 So, g^ (x)= 200 x¹⁹⁹ 200 + 199 x¹⁹⁸ 199 +s+ 2 x 2 +1+0 array ] At ( x=0 ), we have ( g^ (0)=1 )

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