KCET2014MathematicsFunctions
The local minimum value of the function (f^ ) given by (f(x)=3+|x| ), (x R ) is.
Options
- A( 3 )
- B( 0 )
- C( -3 )
- D( 1 )
Correct answer
D. ( 1 )
Step-by-step solution
Given that, f(x)=3+|x| We know that |x|= x² So, f(x)=3+ x² So, f^ (x)= 2 x 2 x² = x |x| Clearly when x>0 ,local minimum =1 When x < 0 , local minimum =-1 So, option (3) and (4) both are true