Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
KCET2018MathematicsHyperbola

The distance between the foci of a hyperbola is ( 16 ) and its eccentricity is ( 2 ). Its equation is

Options

  1. A( x²-y²=32 )
  2. B( x² 4 - y² 9 =1 )
  3. C( 2 x²-3 y²=7 )
  4. D( y²-x²=32 )

Correct answer

A. ( x²-y²=32 )

Step-by-step solution

Given that e= 2 and q e=16 So a=4 2 We know that, b²=a² (e²-1 ) So, b²=32(2-1)=32 General equation of hyberbola is given by, x² a² - y² b² =1 Therefore, x²-y²=32

Practice Hyperbola on Quantrex Academy →

More from Hyperbola

The difference between the distance of any point on the hyperbola from the two foci is 16 and the eccentricity is 2 . Then the equation of the hyperbola is 2026In the figure Statement-I: When > 0 , the section is hyperbola Statement-II: When > 90^ , the section is ellipse Which of the following is correct? 2026If the line y = 2x + is a tangent to the hyperbola 36x^2 - 25y^2 = 3600 , then = 2026If the line 4x + 3y = 7 touches the hyperbola x^2 - y^2 = 7 , then the sum of the co-ordinates of the point of contact is... 2026If the eccentricity of the hyperbola x^2 a^2 - y^2 b^2 =1 passing through the point (4,6) is 2, then the equation of the tangent to this hyperbola at (4,6) is 2025A hyperbola passes through the point P ( 2 , 3 ) and has foci at ( 2,0) . Then the point that lies on the tangent drawn to this hyperbola at P is 2025If is the angle subtended by a latus rectum at the centre of the hyperbola having eccentricity 2 7 - 3 , then = 2025The tangent drawn at an extremity (in the first quadrant) of latus rectum of the hyperbola x^2 4 - y^2 5 =1 meets the x -axis and y -axis at A and B respectively. If O is the origi 2025 Full Hyperbola list All KCET PYQs