KCET2007MathematicsIndefinite Integration
3 x²+1 x²-6 x+8 is equal to
Options
- A3+ 49 2(x-4) - 13 2(x-2)
- B49 2(x-4) - 13 2(x-2)
- C-49 2(x-4) + 13 2(x-2)
- D49 2(x-4) + 13 2(x-2)
Correct answer
A. 3+ 49 2(x-4) - 13 2(x-2)
Step-by-step solution
Given, 3 x²+1 x²-6 x+8 On dividing, we get 3 x²+1 x²-6 x+8 =3+ 18 x-23 x²-6 x+8 Now, 18 x-23 (x-2)(x-4) = A x-2 + B x-4 18 x-23=A(x-4)+B(x-2) 18 x-23=(A+B) x-4 A-2 B Equating the coefficient of x and constant term, we get A+B=18 -4 A-2 B=-23 get A+B=18-4 A-2 B=-23 On solving these equations, we get A=- 13 2 , B= 49 2 18 x-23 (x-2)(x-4) =- 13 2(x-2) + 49 2(x-4) Then, from Eq. (i), we get 3 x²+1 x²-6 x+8 =3- 13 2(x-2) + 49 2(x-4)