Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
KCET2018MathematicsInverse Trigonometric Functions

The value of the expression ( ( 1 2 ⁻¹ 2 5 ) ) is

Options

  1. A( 12- 5 )
  2. B( 5 -2 )
  3. C( 5 -2 2 )
  4. D( 5- 2 )

Correct answer

B. ( 5 -2 )

Step-by-step solution

Given that ( ( 1 2 ⁻¹ 2 5 ) ) Let ( ⁻¹ ( 2 5 )= ) then, ( = 2 5 ) So, ( ( 1 2 ⁻¹ 2 5 )= ( 1 2 ) ) We know that, ( = 1- 2 1+ 2 ) So, ( ( 1 2 )= 1- 1+ ) ( = 1- 2 5 1+ 2 5 = 5 -2 5 +2 ) ( = 5 -2 5 +2 5 -2 5 -2 ) ( = 5 -2 1 = 5 -2 )

Practice Inverse Trigonometric Functions on Quantrex Academy →

More from Inverse Trigonometric Functions

If y = ⁻¹ ( 1+x^3 + 1-x^3 1+x^3 - 1-x^3 ) then dy dx = 2026If X = ⁻¹ [2 (2 ⁻¹ 1 2 ) ] + ⁻¹ [ ( 7 6 ) ] and Y = ⁻¹ [ ( 11 6 ) ] + ⁻¹ [ ( 4 3 ) ] then the value of 2X - Y is: 2026The value of the expression ⁻¹ ( 7 6 ) + ⁻¹ ( 22 3 ) + ⁻¹ ( 4 5 ) is: 2026Which of the following is the simplest form of the expression ⁻¹ ( 1+x^2 - 1 x ) where x 0 2026If ⁻¹ x + ⁻¹ y = 2 , then x^2 is equal to 2026⁻¹ ( 1 1 + 1 2 ) + ⁻¹ ( 1 1 + 2 3 ) + + ⁻¹ ( 1 1 + n(n+1) ) = 2026The second order derivative of ⁻¹(4x^3 - 3x) with respect to ⁻¹(2x^2 - 1) , where 1 2 < x < 1 is 2026If 2 ⁻¹x - 3 ⁻¹x = 4 , then 2 ⁻¹x + 3 ⁻¹x = 2026 Full Inverse Trigonometric Functions list All KCET PYQs