KCET2019MathematicsLimits
( _ r=1 ^ n (2 r-1)=x ) then ( _ n [ 1³ x² + 2³ x² + 3³ ² + + n³ ² ]= )
Options
- A( 1 4 )
- B( 04 )
- C( 1 2 )
- D( 11 )
Correct answer
A. ( 1 4 )
Step-by-step solution
( ( A ) ) ( x=1+3+5+ +(2 n-1) ) ( x=n² ) ( x²=n⁴ ) ( _ n [ 1³+2³+ +n³ x² ] ) ( _ n [ n²(n+1)² 4 n⁴ ] ) ( _ n [ n² n² (1+ 1 n )² 4 n⁴ ] ) ( _ n [ (1+ 1 n )² 4 ]= 1 4 )