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KCET2011MathematicsParabola

The length of the latusrectum of 3 x²-4 y+6 x-3=0 is

Options

  1. A3 4
  2. B4 3
  3. C2
  4. D3

Correct answer

B. 4 3

Step-by-step solution

Given equation of conic 3 x²-4 y+6 x-3=0 array lc & 3 x²+6 x-3=4 y & 3 (x²+2 x-1 )=4 y & 3 (x²+2 x+1-2 )=4 y & 3(x+1)²-6=4 y & 3(x+1)²=4 y+6 Let & (x+1)²= 4 3 (y+3 / 2) & X²= 4 3 Y array X²= 4 3 Y where X=x+1 and Y=y+3 / 2 and 4 b=4 / 3 b=1 / 3 So, now the length of latusrectum is 4 / 3 .

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