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KCET2009MathematicsParabola

A stone is thrown vertically upwards from the top of a tower 64 ~m high according to the law s=48 t-16 t² . The greatest height attained by the stone above ground is

Options

  1. A36 ~m
  2. B32 ~m
  3. C100 ~m
  4. D64 ~m

Correct answer

C. 100 ~m

Step-by-step solution

Given, s=48 t-16 t² ds dt =48-32 t At the greatest height, v = ds dt =0 48-32 t=0 t = 3 2 s =48 3 2 -16 ( 3 2 )²=36 ~m Total height =64+36=100 ~m

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