How many ways can you arrange all the letters and numbers in "KCET 2025" which start with K and end with 5 ?

Step-by-step solution

The given alphanumeric string is KCET 2025. The letters and numbers present are K, C, E, T, 2 , 0 , 2 , 5 . The total number of characters to be arranged is 8 . The first position is fixed for K and the last position is fixed for 5 . The remaining 6 positions are to be filled by the remaining 6 characters: C, E, T, 2 , 0 , 2 . Among these 6 characters, the digit 2 is repeated twice. The number of ways to arrange these 6 characters is 6! 2! . 6! 2! = 720 2 = 360 Answer: 360