KCET2019MathematicsPermutation and Combination
The number of ( 4 ) digit numbers without repetition that can be formed using the digits ( 1,2,3,4 ), ( 5,6,7 ) in which each number has two odd digits and two even digits is
Options
- A( 436 )
- B( 454 )
- C( 432 )
- D( 450 )
Correct answer
C. ( 432 )
Step-by-step solution
(C) Given digits are ( 1,2,3,4,5,6,7 ). Two even digits can be selected in ( 3 2 ) Two odd digits can be selected in ( 4 2 ) ways. These selected ( 4 ) digits can be arranged in ( 4 ! ) ways. ( ) Total number of ways ( = 4 2 3 2 ₂ ! ) ( =6 3 24 ) ( =18 24 ) ( =432 )