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KCET2025MathematicsProbability

A random experiment has five outcomes w ₁, w ₂, w ₃, w ₄ and w ₅ . The probabilities of the occurrence of the outcomes w ₁, w ₂, w ₃, w ₄ and w ₅ are respectively 1 6 , a , b and 1 12 such that 12 a +12 ~b -1=0 . Then the probabilities of occurrence of the outcome w₃ is

Options

  1. A2 3
  2. B1 3
  3. C1 6
  4. D1 12

Correct answer

A. 2 3

Step-by-step solution

array ll p ( w ₁ )= 1 6 & p ( w ₂ )= a & 1 6 + a + b + x + 1 12 =1 p ( w ₃ )= b & 12( a + b + x )=9 p ( w ₄ )= c & a + b + x = 3 4 p ( w ₅ )= 1 12 & 1 12 + x = 3 4 x = 2 3 array

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