KCET2020MathematicsProbability
Corner points of the feasible region determined by the system of linear constraints are (0,3),(1,1) and (3,0) . Let z=p x=q y , where, p, q>0 . Condition on p and q , so that the minimum of z occurs at (3,0) and (1,1) is
Options
- Ap=2 q
- Bp= q 2
- Cp=3 q
- Dp=q
Correct answer
B. p= q 2
Step-by-step solution
The minimum value of z is unique. It is given that the minimum value of z occurs at two points (3,0) and (1,1) array lrl & p(3)+q(0) & =p(1)+q( l ) & & 3 p=p+q & & 2 p=q & & p=q / 2 array