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KCET2018MathematicsProbability

For the probability distribution given by array |c|l|l|l| x = x _ i & 0 & 1 & 2 P _ i & 25 36 & 5 18 & 1 36 array the standard deviation ( ( ) ) is

Options

  1. A( 1 3 )
  2. B( 1 3 5 2 )
  3. C( 5 36 )
  4. DNone of the above

Correct answer

B. ( 1 3 5 2 )

Step-by-step solution

Probability distribution given by array |l|l|l|l| X = x _ i & 0 & 1 & 2 P & 25 36 & 5 18 & 1 36 array We know that, ( M²+ ²= x_ i ² P (x=x_ i ) ) Here ( M= x_ i P (x-x_ i )= 5 18 + 2 36 = 6 18 = 1 3 ) So, ( 1 9 + ²= 5 18 + 4 36 = 7 18 ) ( ²= 7 18 - 2 18 = 5 18 ) Therefore ( = 1 3 5 2 )

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