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KCET2018MathematicsProbability

A bag contains ( 17 ) tickets numbered from ( 1 ) to ( 17 ). A ticket is drawn at random, then another ticket isdrawn without replacing the first one. The probability that both the tickets may show even numbers is

Options

  1. A( 7 34 )
  2. B( 8 17 )
  3. C( 7 16 )
  4. D( 7 17 )

Correct answer

A. ( 7 34 )

Step-by-step solution

Number of tickets are ( 17 ) Even number balls are ( 2,4,6,8,10,12,14,16 ). So, number of even balls are ( 8 ). ( P ) (both tickets show even number) ( = 8 17 7 16 = 7 34 )

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