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KCET2018MathematicsProbability

If ( A ) and ( B ) are mutually exclusive events, given that ( P ( A )= 3 5 , P(B)= 1 5 ), then ( P ( A ) or ( B ) ) is

Options

  1. A( 0.8 )
  2. B( 0.6 )
  3. C( 0.4 )
  4. D( 0.2 )

Correct answer

A. ( 0.8 )

Step-by-step solution

Here ( P(A)= 3 5 , P(B)= 1 5 ) For mutually exclusive events ( A ) and ( B ) ( P(A ) or ( B)=P(A)+P(B) ) ( P(A ) or ( B)= 3 5 + 1 5 = 4 5 )

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