KCET2017MathematicsProbability
The distance of the point ( (-2,4,-5) ) from the line ( x+3 3 = y-4 5 = z+8 6 ) is
Options
- A( 37 10 )
- B( 37 10 )
- C( 37 10 )
- D( 37 10 )
Correct answer
B. ( 37 10 )
Step-by-step solution
Given line, ( x+3 3 = y-4 5 = z+8 6 (1) ) and point ( P (-2,4,-5) ) Let ( x+3 3 = y-4 5 = z+8 6 = ) So, point on line is ( Q(3 -3,5 +4,6 -8) ) Since, ( P Q ) line is perpendicular to line of Eq. (1). SO, [ array l l₁ l₂+m₁ m₂+n₁ n₂=0 (3 -1) 3+5 (5+0)+(6 -3) 6=0 9 -3+25 +36 -18=0 70 =21 = 3 10 array ] Therefore, ( Q (- 21 10 , 55 10 ,- 62 10 ) ) So, [ array l P Q= (- 21 10 -(-2) )²+ ( 55 10 -4 )²+ (- 62 10 -(-5) )² = 1 100 + 225 100 + 144 100 = 370 100 = 37 10 array ]