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KCET2015MathematicsProbability

( ₀^ / 4 ( x+ x x ) d x )

Options

  1. A( 4 2 )
  2. B( 2 2 )
  3. C( 8 2 )
  4. D( 2 )

Correct answer

C. ( 8 2 )

Step-by-step solution

array l Given that I = ₀^ 4 ( x+ x x ) d x = ₀^ 4 (1+ x) d x array As we know that array l ₀^ a f(x) d x= ₀^ a f(a-x) d x Now, I= ₀^ 4 (1+ ( 4 -x ) ) d x = ₀^ 4 (1+ 1- x 1+ x ) d x = ₀^ 4 ( 2 1+ x ) d x = ₀^ 4 2 d x- ₀^ 4 (1+ x) d x I=( 2) ₀^ 4 d x-I 2 I=( 2) 4 I= 8 ( 2) array

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