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KCET2014MathematicsProbability

The set ( A= x ;|2 x+3| < 7 ) is equal to the set.

Options

  1. A( B= x:-3 < x < 7 )
  2. B( C= x:-13 < 2 x < 4 )
  3. C( D= x: 0 < x+5 < 7 )
  4. D( E= x:-7 < x < 7 )

Correct answer

C. ( D= x: 0 < x+5 < 7 )

Step-by-step solution

Given A = x ;|2 x+3| < 7 |2 x+3| < 7 < 2 x+3 < 7 10 < 2 x < 4 -5 < x < 2 0 < x+5 < 7 Therefore, set A= x:|2 x+3| < 7 is equal to D= x: 0 < x+5 < 7

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