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KCET2014MathematicsProbability

How many ( 5 ) digit telephone numbers can be constructed using the digits ( 0 ) to ( 9 ), if each number starts with ( 67 ) and no digit appears more than once ?

Options

  1. A( 336 )
  2. B( 337 )
  3. C( 335 )
  4. D( 338 )

Correct answer

A. ( 336 )

Step-by-step solution

3 digits from 0,1,2,3,4,5,8,9 Arrangement of 8 digits taking 3 at a time is 8 P₃= 8 ! 5 ! =8 7 6=42 8=336

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