KCET2014MathematicsProbability
Consider an infinite geometric series with first term ' ( a ) ' and common ratio ' ( r ) '. If the sum is ( 4 ) and the second term is ( 3 4 ), then
Options
- A( a= 4 7 , r= 3 7 )
- B( a=3, r= 1 4 )
- C( a=2, r= 3 8 )
- D( a= 3 2 , r= 1 2 )
Correct answer
B. ( a=3, r= 1 4 )
Step-by-step solution
Given that, first term is a and common ratio is ( r ). and ( t₂= 3 4 ) ( a r= 3 4 (1) ) Now, ( 4= a 1-r a=4-4 r ) ( 4 r=4-a (2) ) From Eqs. (1) and (2), we get ( a=3, r= 1 4 )