KCET2008MathematicsQuadratic Equation
The real root of the equation x³-6 x+9=0 is
Options
- A-6
- B-9
- C6
- D-3
Correct answer
D. -3
Step-by-step solution
Given, x³-6 x+9=0 (x+3) (x²-3 x+3 )=0 x =-3 or x ²-3 x +3=0 Now, Discriminant, D = 9-4 3 = -3 imaginary Hence, real roots of the given equation is x=-3