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KCET2022MathematicsSets and Relations

Suppose that the number of elements in set A is p , the number of elements in set B is q and the number of elements in A B is 7 , then p^2+q^2=

Options

  1. A50
  2. B51
  3. C42
  4. D49

Correct answer

A. 50

Step-by-step solution

Given, n(A)=p, n(B)=q and n(A B)=7 Since, n(A B)=n(A) n(B) 7=p q p q=7 So, possible values of p and q are 7,1 respectively. p^2+q^2=7^2+1^2=49+1=50

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