KCET2022MathematicsSets and Relations
Let the relation R is defined in N by a R b , if 3 a+2 b=27 then R is
Options
- A(1,12)(3,9)(5,6)(7,3)
- B(0, 27 2 )(1,12)(3,9)(5,6)(7,3)
- C(1,12)(3,9)(5,6)(7,3)(9,0)
- D(2,1)(9,3)(6,5)(3,7)
Correct answer
A. (1,12)(3,9)(5,6)(7,3)
Step-by-step solution
Given relation is 3 a+2 b=27 , where a, b N aligned & 3 a+2 b=27 & b= 27-3 a 2 & a=1 b= 27-3 2 = 24 2 =12 & a=3 b= 27-9 2 = 18 2 =9 & a=5 b= 27-15 2 = 12 2 =6 & a=7 b= 27-21 2 = 6 2 =3 aligned Hence, we can see that all the elements of option (a) satisfies the given relation. Hence, option (a) is correct.