KCET2022MathematicsStraight Lines
If the straight line 2 x-3 y+17=0 is perpendicular to the line passing through the points (7,17) and (15, ) , then equals
Options
- A-5
- B5
- C29
- D-29
Correct answer
B. 5
Step-by-step solution
Equation of line passing through (7,17) and (15, ) is aligned & (y-17)= ( -17 15-7 )(x-7) & y-17= ( -17) 8 (x-7) . & y= ( -17 8 ) x- 7( -17) 8 +17 & aligned On comparing to y=m x+c , we get Slope, m₁= -17 8 It is given that above line is perpendicular to 2 x-3 y+17=0 aligned & y= 2 3 x+ 17 3 & Slope, m₂= 2 3 aligned Condition for perpendicular lines, m₁ m₂=-1 aligned & ( -17 8 ) 2 3 =-1 & -17=-12 =5 aligned