KCET2021MathematicsStraight Lines
The equation of straight line which passes through the point (a ³ , a ³ ) and perpendicular to x +y cosec =a is
Options
- Ax a + y a =a
- Bx -y =a 2
- Cx +y =a 2
- Dx -y =a 2
Correct answer
B. x -y =a 2
Step-by-step solution
Given, Point (x₁, y₁ )= (a ³ , a ³ ) Other line x +y cosec =a aligned y &=- x cosec + a cosec y &= (- ) x+a y &=m₁ x+c m₁ &=- aligned Equation of required line aligned & (y-y₁ )=m (x-x₁ ) & where m= [ m₁ m=-1, m=- 1 m₁ . aligned .=- 1 (- ) = ] (y-a ³ )= (x-a ³ ) y -a ⁴ =x -a ⁴ x -y =a ( ⁴ - ⁴ ) =a ( ² + ² ) ( ² - ² ) x (1) ( 2 )=a 2 x -y =a 2