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KCET2018MathematicsStraight Lines

The equation of the line parallel to the line ( 3 x-4 y+2=0 ) and passing through ( (-2,3) ) is

Options

  1. A( 3 x-4 y+18=0 )
  2. B( 3 x-4 y-18=0 )
  3. C( 3 x+4 y+18=0 )
  4. D( 3 x+4 y-18=0 )

Correct answer

A. ( 3 x-4 y+18=0 )

Step-by-step solution

Given line, 3 x-4 y+2=0 (1) y= 3 4 x+ 1 2 So, m= 3 4 and c= 1 2 Since line is parallel then slope of both lines should same. Then, equation of parallel is given by (y-y₁ )= 3 4 (x-x₁ ) And this line passes through point (-2,3) . Then, (y-3)= 3 4 (x-(-2)) 4 y+12=3 x+6 3 x-4 y+18=0 Therefore, required equation of line is 3 x-4 y+18=0

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