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KCET2019MathematicsTrigonometric Equations

If ( x=| x| ) then, the general solution is

Options

  1. A( x=2 n 4 , n z )
  2. B( x=(2 n+1) I 4 , n Z )
  3. C( x=n 4 , n Z )
  4. D( x=n (-1)^ n 4 , n Z )

Correct answer

A. ( x=2 n 4 , n z )

Step-by-step solution

(A) x=| x| x= x x= 1x=n 4 , n z , but x is positive so x=2 n 4 , n z

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