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KCET2007MathematicsTrigonometric Equations

If 3 = , how many solutions exist such that -2 < < 2 ?

Options

  1. A8
  2. B9
  3. C5
  4. D7

Correct answer

C. 5

Step-by-step solution

We have, 3 = aligned & 3 - =0 & 2 ( 3 + 2 ) ( 3 - 2 )=0 & 2 =0 2 =0 or =0, , 2 & 2 = ( 2 ) or =0, =2 & =0, , 2 & = 4 , 3 4 , 5 4 , 7 4 or =0, , 2 & =0, , 2 aligned Thus, total number of solutions =7

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