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KCET2015MathematicsTrigonometric Ratios & Identities

If ( x ) is real, then the minimum value of ( x²-8 x+17 ) is

Options

  1. A( 11 )
  2. B( 02 )
  3. C( 03 )
  4. D( 04 )

Correct answer

A. ( 11 )

Step-by-step solution

Given that, f(x)=x²-8 x+17 So, f^ (x)=2 x-8 Now, f^ (x)=02 x-8=0 x=4 Now, f^ (x)=2>0 Therefore, f(4)=4²-8(4)+17=1

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