Equation of line passing through the point ( (1,2) ) and perpendicular to the line ( y=3 x-1 )

Step-by-step solution

Given line, y=3 x-1 (1) General equation of line is given by y=m x+c Here m=3 and c=-1 . Condition for two perpendicular lines is m₁ m₂=-1 So, 3 m₂=-1 m₂=- 1 3 Standard equation of line passing through point (x₁, y₁ ) is given by (y-y₁ )=m (x-x₁ ) Here (x₁, y₁ )=(1,2) So, (y-2)=- 1 3 (x-1) -3 y+6=x-1 x+3 y-7=0