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KCET2014MathematicsVector Algebra

Equation of circle with center ( (-a,-b) ) and radius ( a²-b² ) is

Options

  1. A( x²+y²-2 a x-2 b y-2 b²=0 )
  2. B( x²+y²-2 a x+2 b y+2 a²=0 )
  3. C( x²+y²+2 a x+2 b y+2 b²=0 )
  4. D( x²+y²-2 a x-2 b y+2 b²=0 )

Correct answer

C. ( x²+y²+2 a x+2 b y+2 b²=0 )

Step-by-step solution

Given that, center is (-a,-b) and radius is a²-b² Thus, equation of circle is (x+a)²+(y+b)²= ( a²-b² )² x²+y²+2 a x+2 b y+2 b²=0

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