KCET2015PhysicsCommunication System
A stone of mass ( 0.05 ~kg ) is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?
Options
- A( 0.49 ~N ) vertically upwards
- B( 0.49 ~N ) vertically downwards
- C( 0.98 ~N ) vertically downwards
- D( 9.8 ~N ) vertically downwards
Correct answer
B. ( 0.49 ~N ) vertically downwards
Step-by-step solution
Given, mass m =0.05 ~kg When the stone is thrown upwards, force due to gravity acts on the stone vertically downwards, it is given as F=m g=0.05 9.8=0.49 Magnitude of net force =0.49 ~N Direction of net force is vertically downwards.